c++ - What's the output of the following code? -

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• why call default constructor? 3 answers

this code published in http://accu.org/index.php/cvujournal, issue july 2013. couldn't comprehend output, explanation helphful

#include <iostream> int x;  struct {     i() {          x = 0;         std::cout << "--c1\n";     }      i(int i) {         x = i;         std::cout << "--c2\n";     } };  class l { public:     l(int i) : x(i) {}      void load() {         i(x);     }  private:     int x; };  int main() {     l l(42);     l.load();     std::cout << x << std::endl; } 

output:

--c1 0 

i expecting:

--c2 42 

any explanation ?

i(x); equivalent i x;, redundant pair of parentheses thrown in. declares variable named x of type i, default-initialized; not create temporary instance of i x constructor's parameter. see also: most vexing parse