asp.net mvc - How to return to calling page, but with a slight difference, in MVC3? -

i need call mvc3 page(p2) , return calling page(p1). slight twist p2 needs call itself, referrer can end being p2.

so:

p1 - (p2 -> p2 -> p2) ->p1 

so question how p1's referrer url , keep , use later go p1, regardless of number of time p2 calls itself.

i did try , populate viewbag.referrer:

       <a href="@viewbag.referrer">back</a> 

using following controller code, trying set on original call. viewbag.referrer seemed pick p2 referrer url, though in debug mode not resetting viewbag.referrer due isoriginalcall=0. weird. if storing pointer , not value.

        public viewresult index(int id = 0, int isoriginalcall = 0)     {         if (isoriginalcall =1)         {         if (request.urlreferrer != null)         {         viewbag.referrer = request.urlreferrer.localpath;         }         }         viewbag.sliid = id == 0 ? 4 : id;          return view(db.stdsection.where(r=>r.inwizard).orderby(r=>r.name).tolist());     } 

thoughts , solution hugely appreciated. have been going around in circles on one.

thanks in advance.

edit, attempt 2 tempdata:

calling code:

@html.actionlink("sections", "index","ssli2", new { id=item.id, returnurl = request.url.tostring() },null) 

controller:

    public viewresult index(string returnurl, int id = 0)     {         if (returnurl != "x")         {         //viewbag.referrer = request.urlreferrer.localpath;           tempdata["referrer"] = returnurl;         }         viewbag.sliid = id == 0 ? 4 : id;          return view(db.stdsection.where(r=>r.inwizard).orderby(r=>r.name).tolist());     } 

view:

<a href="@tempdata["referrer"]">back</a> 

which produces:

<a href="">back</a> when p2 goes p2, seems use p2 referrer url ???? 

you pass referrerurl in p1 querystring , store value in tempdata. survive transition 1 action call another.

another option pass referrerurl in p1 in querystring , put value in hidden input on p2.

@html.hiddenfor(m => m.referrerurl) 

or

@html.hidden("referrerurl", viewbag.referrerurl) 

then pick value on each post-back , render hidden input value again.

edit

you maybe try doing like:

public viewresult index(string returnurl, int id = 0) {     viewbag.returnurl = returnurl;     viewbag.sliid = id == 0 ? 4 : id;      // can picked in action method.     tempdata["returnurl"] = returnurl;      return view(db.stdsection.where(r=>r.inwizard).orderby(r=>r.name).tolist()); } 

then maybe render using:

<a href="@html.raw(viewbag.returnurl)">back</a>