Dynamically create a dictionary in python 2.4 -

i have query give me results 1 one:

k1=v1 k2=v2 k3=v3 … 

the variable hold result tmp. wanted create dictionary results once result retrieved. tried:

result={}  result.update(tmp) 

i got

valueerror: dictionary update sequence element #0 has length 1; 2 required.

i tried this

result.update(tmp.replace("=",":")) 

i got same err. don'twant substring keys , values use d(k1)=v1 build dict. there other way it? can change query , let generate results k1:v1, k2:v2,... how can dynamically create dictionary in python 2.4? thank you!

if tmp string of k1 = v1 pairs, 1 per line, you'll need parse out pairs:

result = {} result in query:     key, value = result.split('=', 1)     result[key.strip()] = value.strip() 

this presumes query returns individual 'key1=value1' strings split out key , value pairs.

only use result.update() sequence of key-value pairs, or dictionary. passing in string won't work; python treats string sequence of one-character strings, , one-character string not fit requirement key-value pair.