xml parsing - LuaXML parse the XML with multiple tags with the same name -

i'm trying parse data xml files like

<level>   <bg>details1</bg>   <bg>details2</bg> </level> 

with xml.find(bg) can details 1 out. it's because xml.find returns first (sub-)table matches search condition or nil.

if want read both bg out. how achieve in luaxml? or please introduce other lua xml library works.

addons real scenario this

<a>    <b>     <level>       <bg>details1</bg>     </level>     <level>       <bg>details2</bg>     </level>    </b> </a> 

i know need whole b object out , use xml.tag read level out. attempts fail. me on code?

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i solution based on mike corcoran's suggestion.

require 'luaxml'  local text = [[ <a>    <bcde>     <level>       <bg>details1</bg>     </level>     <level>       <bg>details2</bg>     </level>    </bcde> </a> ]]  local txml = xml.eval(text) _, node in pairs(txml:find("bcde"))  if node.tag ~= nil         if node[node.tag] == "level"             local bg = node:find("bg")                 if bg ~= nil                 i=1, #bg                     print( bg[i])                 end             end         end     end end 

there many layers , seems slow.. suggestion improve efficiency?

just iterate on children of level tag (unless there other information in there aren't telling needs filtered)

require 'luaxml'  local text = [[ <level>     <bg>details1</bg>     <bg>details2</bg> </level> ]]  local value = 1  local txml = xml.eval(text) _, node in pairs(txml:find("level"))     if node.tag ~= nil         print(node[value])     end end 

and if need filter out except <bg> tags, can modify loop this:

for _, node in pairs(txml:find("level"))     if node.tag ~= nil         if node[node.tag] == "bg"             print(node[value])         end     end end