python - Why can't I iterate through list of lists this way? -


sorry i'm new python, needed take 6 individual lists , concatenate them such resemble list of lists.

i.e. a1 list + b1 list b + c1 list c , a2 list + b2.... etc

should become [[a1,b1,c1], [a2,b2,c2]...]

i tried this:

comblist = [[0]*6]*len(lengthlist)  in range(len(lengthlist)):     print     comblist[i][0] = poslist[i]     comblist[i][1] = widthlist[i]     comblist[i][2] = heightlist[i]     comblist[i][3] = arealist[i]     comblist[i][4] = perimlist[i]     comblist[i][5] = lengthlist[i]     # i++ print comblist

and tried variation appended instead:

    in range(len(lengthlist)):         print         comblist[i][0].append(poslist[i])         comblist[i][1].append(widthlist[i])         comblist[i][2].append(heightlist[i])         comblist[i][3].append(arealist[i])         comblist[i][4].append(perimlist[i])         comblist[i][5].append(lengthlist[i])         # i++     print comblist

so have 2 questions.

why didn't either of work, cus in mind should have. , don't need put i++ @ bottom right? reason wasn't working trouble shooting.

i ended finding solution, below, i'd understand happened in above 2 codes failed terribly. 

for j in range(len(fnamelist)):             rows = [fnamelist[j], widthlist[j], heightlist[j], arealist[j], perimeterlist[j], lengthlist[j]]             print rows             comblist.append(rows)         print comblist

the issue @ did creating list of 6 references same thing.

[0]*6 generate list of 6 references same number (zero), , [[0]*6]*len(lengthlist) generate list of references same [0]*6 list.

i think function want zip:

a = ['a1','a2','a3'] b = ['b1','b2','b3'] c = ['c1','c2','c3']  print [x x in zip(a,b,c)]

which gives:

[('a1', 'b1', 'c1'), ('a2', 'b2', 'c2'), ('a3', 'b3', 'c3')]

so in case, work:

comblist = [x x in zip(fnamelist, widthlist, heightlist, arealist, perimeterlist, lengthlist)]

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