Converting row names into one columns in R and export to txt file -

i have multiple same names in row different dates , values corresponding it. want consolidate rows , make columns date , value. idea how in r? (i m learing r)

id  date    value 62  17/03/2008  1 62  29/09/2008  9 62  01/01/2009  0 66  01/04/2009  6 66  29/06/2009  3 66  30/09/2009  5 75  01/01/2010  6 75  01/04/2010  0 91  01/07/2010  8 91  28/09/2010  0 

i want convert below

 62        62   66        66    75         75 17/03/2008  1   01/04/2009  6   01/01/2010  6 29/09/2008  9   29/06/2009  3   01/04/2010  0 01/01/2009  0   30/09/2009  5    

once done, want write output files groups(e.g. 62, 66, 75) in txt format name of txt file group names prefix 'a'(e.g. 62a.txt, 66a.txt, 75a.txt). have long dataset hence sort of looping has done.

what kind of output want? want split data according id? return list entry each id. here's data.frame, reproducible example. similarly, should provide structure of desired output.

df <- structure(list(id = c(62l, 62l, 62l, 66l, 66l, 66l, 75l, 75l,        91l, 91l), date = structure(c(6l, 9l, 1l, 3l, 8l, 10l, 2l, 4l,        5l, 7l), .label = c("01/01/2009", "01/01/2010", "01/04/2009",        "01/04/2010", "01/07/2010", "17/03/2008", "28/09/2010", "29/06/2009",        "29/09/2008", "30/09/2009"), class = "factor"), value = c(1l,        9l, 0l, 6l, 3l, 5l, 6l, 0l, 8l, 0l)), .names = c("id", "date",        "value"), class = "data.frame", row.names = c(na, -10l)) 

this think want do:

split(df, df[,"id"]) split(df[,c("date", "value")], df[,"id"])